Hello HG,
You have said a while ago that the joker does not receive a piece value. You have also said that the sum of the squares of the values of the opponent's pieces over the sum of the values of said pieces could be a good approximation. This should not be hard to implement, when you have the time, otherwise as the computer makes some funny decision.
Hello HG, You have said a while ago that the joker does not receive a piece value. You have also said that the sum of the squares of the values of the opponent's pieces over the sum of the values of said pieces could be a good approximation. This should not be hard to implement, when you have the time, otherwise as the computer makes some funny decision.