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00:00 - 00:59 | Indian question we have to prove the given figure metric identity so here that one is equal to 1 divided by 1 + sin a + here it is 1 divided by 1 minus sin a is equal to 2 sin square A so here we take the left hand side of this trigonometric identities so here that one is equal to left hand side so here it is 1 divided by 1 + sin a + 1 divided by 1 minus sin a so here here now we take the LCM so here in the denominator here we get 1 + sin a and then 1 - sin and here here we get 1 - sin here it is sin a year that one is sin a and n + 1 + sin a Sohail this Sin A minus Sin A + B = |

01:00 - 01:59 | 20 and then one plus one will be equal to 2 so here here we get is equal to 2 and in the denominator here we get one square minus sin square using the algebraic identity which is a + b into a minus b is equal to a square minus b square so here here it that one is equal to 2 divided by 1 minus 8 will be sin square A now we know the trigonometric identity according to which year sin square A + cos square A is equals to 1 so here we get sin square is equals to here we get sin square is equal to 1 minus cos square A so here here statement is equal to 2 divided by 1 minus 1 minus cos square A show that will be equals to 2 / 1 -1 and 1 + cos |

02:00 - 02:59 | square Sudesh 1 - 1 will be zero so here we get 2 / cos square A and that can that can also be written as to sec square A because because here cos A is equal to 1 by a and hear that one is equal to right hand side and that's the answer |

**What is identity?**

**Prove `sin^2 theta + cos^2 theta=1`**

**Prove `sec^2 theta = 1+ tan^2 theta`**

**Prove `cosec^2 theta = 1 + cot^2theta`**

**Show : `2 sec^2 theta - sec^4 theta - 2 cosec^2 theta + cosec^4 theta = cot^4 theta - tan^4 theta`**

**For any acute angle `theta`; Prove (i) tan `theta` = sin`theta`/cos`theta` (ii) cot `theta` = cos `theta`/sin`theta`**

**Prove `1/(1+sintheta)+1/(1-sintheta) = 2 sec^2 theta`**

**Show : `(1+tan^2theta)(1+sintheta)(1-sintheta) = 1`**

**If `cos theta + sintheta = sqrt2 cos theta`; show that `costheta- sintheta = sqrt2 sintheta`**

**If `acostheta-b sintheta =c`; prove that `a sin theta + b costheta = pmsqrt(a^2+b^2-c^2)`**